Home / Science, Engineering & Maths / Thermodynamics in Energy Engineering / Example 1 : supercooled water
Example 1 : supercooled water
Exercise 1
If the system is insulated (adiabatic), -10℃ H({2})O((l)) (supercooled liquid) will be transformed to ice + liquid H({2})O at 0℃. Calculate fraction of ice in the final mixture.
Basis : 1 mole of initial supercooled liquid.
- Since the system is adiabatic, Qp=ΔHtotal=0.
- In calculating enthalpy changes, take the reversible path. The enthalpy change of reversible path is the same with that of the original change since enthalpy is a state function.
- Regard the process as follows.
- Adiabatic : ΔHtotal=ΔH1+ΔH2=0
Meaning: the heat needed heating H2(l)from-10℃ to 0℃ is
provided by solidification of xmole of H2(l)from-10℃ to H2(s)0℃.
The latent heat is evolved from the solidification process.
Reach your personal and professional goals
Unlock access to hundreds of expert online courses and degrees from top universities and educators to gain accredited qualifications and professional CV-building certificates.
Join over 18 million learners to launch, switch or build upon your career, all at your own pace, across a wide range of topic areas.
