Hamdi Douss

Hamdi Douss

Location Tunis - Tunisia

Activity

  • If you have a symmetric pattern, like just a line from the center to the edge of the triangle, this is normal. You only have a different pattern if you turn the flexagon upside down. However, if you'll write different letters or different symbols, you'll get different patterns, you'll see the letters turn around. Try to flex your flexagon without rotating the...

  • It is not clear what the definition of a state is. But if I try to not turn the flexagon while cycling between faces (so I don't induce a state forward manually), I think I got 6 states for each face.

  • @SylviaO'Mahony you had the same error as mine: the diagonal going from upper left to bottom right has the number '4' twice

  • Thanks for all! That's true. I don't know why I just checked the diagonal from upper right to bottom left and not the other.

  • Is this another valid solution for the Latin square?
    1 7 4 5 2 3 6
    6 3 1 2 5 7 4
    3 2 6 7 4 1 5
    4 5 2 3 7 6 1
    7 6 5 4 1 2 3
    5 1 7 6 3 4 2
    2 4 3 1 6 5 7

  • @YossiElran Even after editing, it is still wrong (I think). The only thing that can make Issac the mistake maker is that Abraham did not write any part. Else, If Abraham 1st statement is true (Issac is the mistake maker), that makes his 2nd statement false, and thus he wrote that wrong part of the essay.

  • I think the explanation on Question 4 is wrong: "Correct! He could be diurnal and asleep (and lying) or nocturnal and awake (and telling the truth)." -> should be "Correct! He could be diurnal and asleep (and lying) or nocturnal and asleep (and telling the truth)."

  • @JanDeurwaarder 2 boys, 2 girls, 6 pennies to get 6 buns and 1 penny to get 2 buns -> 8 buns, 2 for each of the kids.

  • I find a solution with 2 boys and 2 girls, so I think the answers given in the email are not unique.

  • @JanDeurwaarder This is a substitution encoding, but not a simple shift, it is more subtle than that..subtle like a mirror!

  • @JanDeurwaarder Why? I solved it! (about @JoB code)

  • Hamdi Douss made a comment

    AMNKY RGUJN SYSFO GUSGK HANBC ZNEGT YFRPV MSRZV HNQEV KCBDQ Q.

  • ZYHLOFGVOB!

  • It would have been nice to know in advance that the number of trials we could make on an exercice is limited. Ideally, the number of trials in each exercice is displayed.

  • What are the motivations behind the fact to have one encoding for left-hand digits, and another for the right-hand ones?

  • @YossiElran Absolutely. I missed that. Thanks for the reply.

  • The solving approach in the video made these assumptions/guessing: K=1, and O=7. A more formal approach would be: K is 1 or 2. 5th column: 4*4=16, so O is 6, 7, 8 or 9 (the remainder is utmost 3), and the remainder for the last column is necessarily 1 => K*4+1=J. So J is 5 or 9. Now, let's take the 2nd column: J*4. Given O > 6, the remainder from the first...

  • Anyone else googled "cyclic number" after reading @RubyHoward comment?

  • For the question 1, quiz in 1.17 activity: DOPEY+DOPEY=GRUMPY. I came up with another solution: 93210+93210=186420. Is it also correct or am I missing something?

  • I did not know about "divisible by 11" rule! Awesome!