4.6

## UNSW Sydney

Skip to 0 minutes and 10 secondsNow we can interpret the experiments on finding centres of gravity by the suspension method. We'll start with the triangular shape. Here's an FBD of the triangular cardboard shape. There is a force at the pin and a force from the weight acting at the centre of gravity. Because it can be assumed to be a two-force object, the centre of gravity must be along this line. It must be along this second line, too. So the centre of gravity must be where these two lines cross. We can check it out. In our test, we made a third measurement. Here's the result. The three lines almost meet at a point. You would expect a little triangle, depending on how careful you had been.

Skip to 0 minutes and 59 secondsThere's a standard result for the location of the CG of a triangle. It finds many applications in engineering. The centre of gravity is one-third of the height up from any side taken as base, like this, and this, and this.

Skip to 1 minute and 32 secondsHere's the card from the test with the one-third point marks. Again, I think the agreement isn't bad. But where does this result for a triangle come from? The classic proof involves calculus, but you can also see it by considering the triangle to be made up of a lot of narrow strips. Each strip is roughly a rectangle with its CG in the middle, so the CG must be along this line connecting the narrow strips. For fun, you could show that this method gives the one-third height rule. Now to the balancing method-- when the card balances, the centre of gravity must lie along the line of balance. Imagine taking moments about the line of balance.

Skip to 2 minutes and 24 secondsFor equilibrium, the moment arm for the weight must be zero, so the CG must, indeed, be on the line of balance. We rotated the card and found another line of balance. The estimated CG is where they cross. Here, we found the centre of the square by drawing diagonals. What do you think of the agreement?

Skip to 2 minutes and 52 secondsBecause our cardboard is uniform in density, we have also found its centre of volume. The centre of gravity might be the same location as the centre of volume, but it isn't always-- for example, if the object is made up of materials which have different densities. And because out cardboard is uniformly thick and a flat shape, we have also found the centre of area. These geometric properties are called centroids. It's a term that often appears in engineering. Now let's find out how to calculate centres of gravity and centroids.

# Analysis: Interpreting the tests

Although the two methods look quite different, in both cases the weight vector passes through the pivot so that its moment arm is zero.

This video explains in detail how this condition can be used to locate the centre of gravity.